Question

How do you use synthetic division to divide `(x^5-13x^4-120x+80)/(x+3)`?

Answer 1

D= `x^5-13x^4 - 120 x+80`
d= `x+3`
`x+3=0 rArr x=-3`
Then create the following table,

-856 is the remainder and rest is the quotient,
`x^4-16x^3+48x^2-144x +312 - 856/(x+3)`