How do you solve #92= 4( 8k - 1)#?

1 Answer
Jumbotron
Aug 31, 2017

#k = 3#

Explanation:

#92 = 4(8k - 1)#

Multiply the bracket

#92 = 32k - 4#

Collect like terms

#92 + 4 = 32k#

#96 = 32k#

Divide both sides by coefficient of #k#

#96/32 = (cancel32k)/cancel32#

#96/32 = k#

#k = 3 -> Answer#

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