How do you solve #3x - 6= 2x + 22#?

1 Answer
smendyka
Aug 31, 2017

See a solution process below:

Explanation:

Add #color(red)(6)# and subtract #color(red)(2x)# to solve for #x# while keeping the equation balanced:

#-color(red)(2x) + 3x - 6 + color(red)(6) = -color(red)(2x) + 2x + 22 + color(red)(6)#

#(-color(red)(2) + 3)x - 0 = 0 + 28#

#1x = 28#

#x = 28#

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