How do you simplify #\frac { \frac { 6} { m - n } + \frac { 6} { m } } { 2m - n }#?

1 Answer
Aug 31, 2017

I got #(6/(m-n)+6/m)/(2m-n) = color(red)(6/(m^2-mn))#
(...but you might want to check this)

Explanation:

#6/(m-n)+6/m#
#color(white)("XXX")=(6m+6(m-n))/((m-n)m)#

#color(white)("XXX")=(6(2m-n))/(m^2-mn)#

So
#(6/(m-n)+6/m)/(2m-n)#
#color(white)("XXX")=((6(2m-n))/(m^2-mn))/(2m-n)#

#color(white)("XXX")=(6(cancel(2m-n)))/(m^2-mn)xx1/cancel(2m-n)#

#color(white)("XXX")=6/(m^2-mn)#