What is #3sqrt(8^2)# ?

3 Answers
Aug 31, 2017

#3*sqrt(8^2) = 24#

Explanation:

We need to find #3*sqrt(8^2)#. Since squaring and square rooting are inverse functions, they cancel out, leaving just #3*8=24#.

Aug 31, 2017

#root(3)(8^2) = 4#

Explanation:

Assuming the intended expression was #root(3)(8^2)#, we find:

#root(3)(8^2) = root(3)((2^3)^2) = root(3)((2^2)^3) = 2^2 = 4#

Aug 31, 2017

Assuming #root3(8^2)#, we could also write this as:

#root3(8^2)=8^(2/3)=(2^3)^(2/3)=2^2=4#

This used:

  • #rootb(x^a)=x^(a/b)#
  • #(x^a)^b=x^(ab)#

And the ability to prime factorize, that is, know that #8=2*2*2=2^3#.