How do you solve the system of equations $-2x + 2y = - 12$ and $- 2x - 3y = 13$ ?

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Answer 1 · 2017-09-01T09:22:27

$x=31,y=25$

Let $-2x+2y=-12$ be equation 1 and $-2x-3y=13$ equation 2.

Subtract equation 2 from equation 1
$-2x+2y=-12 (-)-2x-3y=13$
$-y=-25$
$y=25$

Substitute $y=25$ into equation 1 to find the value of $x$
$-2x+2(25)=-12$
$-2x+50=-12$
$-2x=-62$
$x=31$

How do you solve the system of equations -2x + 2y = - 12-2x + 2y = - 12 and - 2x - 3y = 13- 2x - 3y = 13?