How do you simplify #\frac { 3x - 2} { 4- 6x } #?

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Answer 1 · 2017-09-03T02:05:17

#-1/2#

Let's first notice that with the two #x# terms #3x# and #-6x#, we can say that:

#-2xx3x=-6x#

The same is true for the non-#x# terms:

#-2xx(-2)=4#

We can take advantage of this:

#(3x-2)/(4-6x)#

#(3x-2)/((-2)(3x-2))#

We can now cancel out the #3x-2# terms and be left with:

#(cancel(3x-2))/((-2)(cancel(3x-2)))#

#1/(-2)=-1/2#