A projectile is fired vertically upward and is s feet above the ground t seconds after being fired, where s=256t — 16t^2. Find (a) the speed of the projectile 4 seconds after being fired, Complete question is in the image ?
1 Answer
Sep 3, 2017
Velocity => ds/dt = 256 - 32t
Hence, after 4 seconds we have:
ds/dt = 256 - 32(4) => 128 feet/sec
Maximum height is acheived when ds/dt = 0
i.e. when 256 - 32t = 0
=> t = 256/32 = 8 seconds
so, maximum height is
i.e.
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