Question

How would the volume if a gas in a piston under `14*"bar"` pressure with a volume of `312*mL`, were reduced in pressure to `7*"bar"` pressure?

Answer 1

Would it not be around `7*"bar"`.........?

Explanation:

Old Boyle's Law holds that given constant temperature, and for a given amount of gas.....`Pprop1/V`........

Else, `PV=k`, and thus solving for `k` at different pressures and volumes......

`P_1V_1=P_2V_2`

And so......`P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar"`.