How do you write the equation of a line given point (6,5 ) and are parallel to and perpendicular to the line with equation y + 5x=8?

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Answer 1 · 2017-09-05T10:33:50

Parallal line is # y = -5x +35 # and perpendiclur line is
# y = 1/5x +19/5 #

The slope of the line #y+5x=8 or y = -5x +8# is

# m= -5 ; [y=mx+c]# . Parallal lines have equal slope i.e #-5)

and the product of slopes of perpendiclur lines is #-1 :. m= 1/5#.

The equation of line passing through #(x_1,y_1)# is

# y-y_1 = m(x-x_1)#.

The equation of line passing through #(6,5)# , parallal to line

#y = -5x +8# is # y - 5 = -5(x-6) or y = -5x +35 # and

the equation of line passing through #(6,5)# , perpedicular to

line #y = -5x +8# is # y - 5 = 1/5(x-6) or y = 1/5x -6/5 +5 # or

# y = 1/5x +19/5 # [Ans]