Question

What are the oxidation states of each element that comprise the interhalogen, `I-F`?

Answer 1

Well, fluorine usually assumes an oxidation state of `-I`....and it does so here.....

Explanation:

The sum of the oxidation numbers EQUALS the charge on the ion, and since we gots a neutral molecule, we have therefore `stackrel(+I)I`.

What are the oxidation numbers for the elements in `F_2`, and for both elements in `IF_7`?

Answer 2

Oxidation number of fluorine `= - 1`

Explanation:

Are you trying to spell Fluorine??

Well the Compound Name is Iodine mono fluoride or Iodine (I) fluoride `("IF")`

Since the Oxidation Number of Iodine is `1`

Hence...

Oxidation Number `rArr "IF" = 1 + F = 0`

`color(white)(xxxxxxxxxxx) rArr F = -1`