How many #"microlitres"# are in a volume of #1.22xx10^-23*cm^3#?

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Answer 1 · 2017-09-06T19:13:59

#1.22 times 10^(- 20)# #mu "L"#

The volume of a single aluminium atom is #1.22 times 10^(- 23)# #"cm"^(3)#.

#1# #"cm"^(3)# is equivalent to #0.001# #"L"#, or #10^(- 3)# #"L"#.

So, #1.22 times 10^(- 23)# #"cm"^(3)# is equivalent to #1.22 times 10^(- 23) times 10^(- 3) = 1.22 times 10^(- 26)# #"L"#.

Now, to go from litres #("L")# to micro-litres #(mu "L")#, we multiply the value by #10^(6)#.

Therefore, #1.22 times 10^(- 26)# #"L"# is equivalent to #1.22 times 10^(- 26) times 10^(6) = 1.22 times 10^(- 20)# #mu "L"#.

Answer 2 · 2017-09-06T19:17:33

Well, there are #1000*cm^3*L^-1#....agreed?

And #10^6*muL*L^-1#.........

And thus #1*L-=10^6*muL-=1000*cm^3#.

And so..............

#1.22xx10^-23*cancel(cm^3)xx10^-3*cancelL*cancel(cm^-3)xx10^6*muL*cancel(L^-1)#

#=1.22xx10^-20*muL#..........which is not a large volume......please check my calculations.....