Question

How do you write `y=4/3(x-2)^2-5` in standard form?

Answer 1

See below.

Explanation:

`4/3( x - 2)^2 -5`

Square the bracket first. `4/3( x^2 - 4x + 4 ) - 5`

Multiply bracket by `4/3`

`(4x^2)/3 - 4/3x + 4/3 - 5`

Simplify:

`4/3x^2 - 4/3x - 11/3`