Question

Given that `(f \cdot g)(x) = (x+1)/2`, and `g(x) = 2x-1`, what is `f(x-3)`?

Answer 1

If `g(x)=2x-1`, `g^(-1) (x)=(x+1)/2`

After plugging `g^(-1) (x)` into first function, I found `f(x)=(x+3)/4`

Hence `f(x-3)=x/4`

Explanation:

1) I found `g^(-1) (x)`

2) I plugged `g^(-1) (x)` for finding `f(x)`

3) I plugged `x-3` in place of `x` for finding `f(x-3)`