How do you solve # 40= - 8y - 22#?

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Answer 1 · 2017-09-08T04:59:22

#y = -7.75#

#40 = - 8y-22#

#:. 40+22=-8y#

#:. 62=-8y#

#:. 62/(-8)=y#

#:. -7.75=y#

Answer 2 · 2017-09-08T07:44:43

#y =-7 3/4 =-7.75#

Notice that the #y#-term is negative.
Adding #8y# to both sides will give a positive #y# term on the left.

#40color(blue)(+8y)= -8ycolor(blue)(+8y)-22#

Subtracting #40# from both sides will isolate the #y#-term.

#40 color(red)(-40) +8y = -22 color(red)(-40)#

#8y = -62#

#y= -62/8 = -31/4#

#y = -7 3/4#