Question #648c3
2 Answers
Sep 10, 2017
Explanation:
We have
Differentiating both sides with respect to
Sep 10, 2017
Explanation:
"differentiate using the "color(blue)"chain rule"
"given "y=(f(g(x))" then"
dy/dx=f'(g(x)xxg'(x)larr" chain rule"
y=1/(cos^2 3x)=(cos3x)^(-2)
rArrdy/dx-2(cos3x)^(-3)xxd/dx(cos3x)
color(white)(y)=-2(cos3x)^(-3)xx-sin3x xxd/dx(3x)
color(white)(y)=(6sin3x)/(cos3x)^3
color(white)(y)=6tan3x xx1/(cos 3x)^2
color(white)(y)=6tan3xsec^2 3x