Question #3c650

1 Answer
Sep 10, 2017

The limit is zero.

Explanation:

As #x rarr 0^-, 1/x rarr -oo.#
For such x, #e^(1/x) rarr 0# and the denominator of the expression goes to 1.
Therefore
As #x rarr 0^-, x/(1 + e^(1/x)) rarr 0.#

As #x rarr 0^-+ 1/x rarr oo.#
For such x, #e^(1/x) rarr oo# and the denominator of the expression goes to #oo#.
Therefore
As #x rarr 0^+, 1/(1 + e^(1/x)) rarr 0,# and
as #x rarr 0^+, x/(1 + e^(1/x)) rarr 0.#

Since the two one-sided limits exist and are equal, the overall limit is zero.