Question #95e4b
2 Answers
This is
Simple harmonic motion (I know u know this ),
For simple harmonic motion Equation is written as
k=Force constant,
AS ,
k=
k=
So substitute here get lambda
And ,
frequency=
c is speed of light=
Intensity=[Power]/area
Intensity is inversely proportional to
So,
Intensity=
So,
divide both of them i.e as 45 and ant 90,
Given equation represents a transverse wave with general equation as
#y(x,t)=Asin ((2pi)/lambda)(x-vt)# .......(1)
where#A# is maximum amplitude,#lambda# is wavelength and#v# wave velocity. Also#-vt# implies velocity in#+x# direction
It also represents Traveling Wave Solution for an ideal string.
it's equivalent form can be written as
#y(x,t)=Asin 2pi(x/lambda-t/T)# ........(2)
where#T# is time period and related to frequency as#f=1/T#
Rewriting given equation in the form as in equation (2) we get
#y(x,t)=5.5sin 2pi(0.010x-2.0t)#
Comparing with (2)
#1/lambda=0.010=>lambda=1/0.010=>lambda=100cm#
#1/T=2.0=>f=2.0Hz#