Question #a7f09

Question

1178 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-11T10:29:21

#|vec("A")| = sqrt(106)#

The vector #"A"# has components #a_(x) = - 5# #"m"# and #a_(y) = 9# #"m"#.

This can be written as:

#Rightarrow vec("A") = - 5 i + 9 j#

The magnitude of a vector is of the form:

#Rightarrow |vec("A")| = sqrt(x^(2) + y^(2))#

Substituting the relevant values:

#Rightarrow |vec("A")| = sqrt((- 5)^(2) + (9)^(2))#

#Rightarrow |vec("A")| = sqrt(25 + 81)#

#therefore |vec("A")| = sqrt(106)#

Therefore, the magnitude of vector #"A"# is #sqrt(106)#.