Question #a2c73

1 Answer
Sep 12, 2017

#e^ln(13)#

Explanation:

We are trying to solve.

#e^x = 13#

Taking logarithms of both sides:

#lne^x = ln(13) => xlne = ln(13)#

Dividing both sides by #lne#

# x = ln(13)/(lne)#

By laws of logarithms the log of the base is always 1.

Example #log_2(2) = 1# , #log_10(10) = 1#

so #lne = 1#

So we have:

#x = ln(13)#

Hence:

#e^ln13= 13#