Question #a2c73

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Answer 1 · 2017-09-12T15:39:24

#e^ln(13)#

We are trying to solve.

#e^x = 13#

Taking logarithms of both sides:

#lne^x = ln(13) => xlne = ln(13)#

Dividing both sides by #lne#

# x = ln(13)/(lne)#

By laws of logarithms the log of the base is always 1.

Example #log_2(2) = 1# , #log_10(10) = 1#

so #lne = 1#

So we have:

#x = ln(13)#

Hence:

#e^ln13= 13#