Question

Question #5155e

Answer 1

`{- frac(a)(2), a, 2 b}`

Explanation:

We have: `5 (x - a) (2 b - x) (2 x + a) = 0`

Dividing through by `5`:

`Rightarrow (x - a) (2 b - x) (2 x + a) = 0`

Using the null factor law:

`Rightarrow x - a = 0 therefore x = a`

`or`

`Rightarrow 2 b - x = 0 Rightarrow 2 b = x therefore x = 2 b`

`or`

`Rightarrow 2 x + a = 0 Rightarrow 2 x = - a therefore x = - frac(a)(2)`

Therefore, the solution set to the equation is `{- frac(a)(2), a, 2 b}`.