Given that #log(a)2 = x#, find #log(a)2a# in terms of #x#?
1 Answer
Sep 13, 2017
Explanation:
#"using the "color(blue)"laws of logarithms"#
#•color(white)(x)logx+logyhArrlog(xy)#
#•color(white)(x)log_a(a)=1#
#rArrlog_a(2a)=log_a(2)+log_a(a)#
#color(white)(xxxxxxxx)=x+1#
