How do you evaluate #(\frac { \sqrt { 3} } { 2} ) ( \frac { 4- \sqrt { 6} } { 3} )#?

1 Answer
ErmWhat
Sep 15, 2017

#(4sqrt(3)-3sqrt(2))/6#.

Explanation:

First, we expand the expression:
#(sqrt(3)*(4-sqrt(6)))/(2*3) = (4sqrt(3)-sqrt(18))/6#
Simplifying the radicals... (#sqrt(18)=3sqrt(2)#)
#(4sqrt(3)-3sqrt(2))/6#
Unfortunately, we can't simplify this further, so this is the answer.

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