Question

Question #f889b

Answer 1

We are trying to differentiate:
`4^(sqrt(21^3-2x+1/x))`. First thing to do is use the chain rule, and we get:

`4^(sqrt(21^3-2x+1/x))*ln(4)*d/dx(sqrt(21^3-2x+1/x))`.
Using the chain rule one more time...

`ln(4)*4^(sqrt(21^3-2x+1/x))(d/dx(21^3-2x+1/x))/(2sqrt(21^3-2x+1/x))`

The derivative of a constant is `0`, the derivative of `-2x` is `-2` and the derivative of `1/x` is `-1/x^2`.

`ln(4)*4^(sqrt(21^3-2x+1/x))(-2-1/x^2)/(2sqrt(21^3-2x+1/x))`

And you should be done!

P.S. I may have gotten something wrong, but this equation ended up being massive so it was kinda inevitable.