Given point (-5,12) how do you find the distance of the point from the origin, then find the measure of the angle in standard position whose terminal side contains the point?

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Answer 1 · 2017-09-15T11:51:43

Distance of point from origin is #13# unit and is at an angle of
#247.38^0# from #0^0#

Point is at # (-5 ,12) # and origin is at #(0,0) # , We know

the distance between two points # (x_1,y_1) and (x_2 , y_2)# is

#D= sqrt((x_1-x_2)^2 + (y_1-y_2)^2) # or

#D= sqrt((-5-0)^2 + (12-0)^2) = sqrt 169 =13# . The point is on

#3#rd quadrant . #tan alpha = 12/5 :. alpha = tan^-1(12/5) # or

# alpha= 67.38^0 :. theta = 180+ 67.38 = 247.38^0#

Distance of point from origin is #13# unit and is at an angle of

#247.38^0# from #0^0# [Ans]