How do you find the value of the discriminant and state the type of solutions given #4a^2=8a-4#?
1 Answer
Sep 15, 2017
Explanation:
#"rearrange the quadratic equating to zero"#
#rArr4a^2-8a+4=0larrcolor(blue)" in standard form"#
#"with "a=4,b=-8,c=4#
#Delta=b^2-4ac=(-8)^2-(4xx4xx4)#
#color(white)(xxxxxxxxx)=64-64=0#
#color(blue)"Types of solutions"#
#• " if "Delta>0" roots are real and different"#
#• " if "Delta=0" roots are real and equal"#
#• " if "Delta<0" roots are not real"#
#"here "Delta=0rArr" roots are real and equal"#
#color(blue)"As a check"#
#"solving "4a^2-8a+4=0#
#rArr4(a^2-2a+1)=0#
#rArr4(a-1)(a-1)=0#
#rArra=1" or "a=1larrcolor(red)" real and equal"#