How do you solve #4x + 3x - 6= 8#?

2 Answers
Sep 15, 2017

See a solution process below:

Explanation:

First, combine like terms on the left side of the equation:

#(4 + 3)x - 6 = 8#

#7x - 6 = 8#

Next, add #color(red)(6)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#7x - 6 + color(red)(6) = 8 + color(red)(6)#

#7x - 0 = 14#

#7x = 14#

Now, divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:

#(7x)/color(red)(7) = 14/color(red)(7)#

#(color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7)) = 2#

#x = 2#

Sep 15, 2017

#x# = #2#

Explanation:

First, you combine the like terms. In this case, that is the 3x and 4x.

#4x + 3x - 6 = #8#

#3x + 4x = 7x#

Then substitute it back into the equation:

#7x - 6 = 8#

Then you can subtract the #-6# from the left side of the equation.

#7x = 8 + 6#
#7x = 14#

And finally, simplify by dividing both sides by 7:
#x = 2#

Hope this helps!