Solve the equation #x^2+12=0#?
1 Answer
Sep 17, 2017
# - 2sqrt(3)i # and#x= 2sqrt(3)i#
Explanation:
We have:
# x^2 = -12 #
Taking square roots we have:
# x = +- sqrt(-12) #
# \ \ = +- sqrt(3*4)i #
# \ \ = +- 2sqrt(3)i #