If #f(x)=e^(6x)#, #g(x)=2x+2# and #h(x)=sqrtx#, what is #f(g(h(x)))#?

1 Answer
Sep 18, 2017

#f(g(h(x)))=e^(12sqrtx+12)# or #e^12e^(6sqrtx)#

Explanation:

We have #f(x)=e^(6x)#, #g(x)=2x+2# and #h(x)=sqrtx#

hence #g(h(x))=g(sqrtx)=2sqrtx+2#

and #f(g(h(x)))=f(2sqrtx+2)#

= #e^(6(2sqrtx+2))#

= #e^(12sqrtx+12)#

= #e^12e^(6sqrtx)#