How do you simplify #(91.2\cdot 10^ { 2} ) \cdot ( 3.972\cdot 10^ { 11})#?

1 Answer
Sep 19, 2017

#=3.622464 *10^15#

Explanation:

To simplify this equation, we do three steps. Since multiplication is commutative ( which means #a*b=b*a#), we shuffle around the equation so it looks the first step looks like this
#(91.2*3.972)(10^2*10^11)#

Next we solve the brackets, remembering that #a^m * a^n= a^(m+n)#, which leaves us with
#(362.2464)(color(red)(10^(2+11)))#
#=(362.2464)(10^13)#
#= 362.2464 * 10^13#

The last step is to simplify the equation. When multiplying a number by a power of 10, the standard thing to do is get that number into the single digits. Remembering that when you add #n# onto #10^x#, the deimal place moves #n# spots to the left on the number in front of 10 and vice-versa, we get
#362.2464 * 10^13 = color(red)(36).color(red)(22464) *10^color(red)(14)=color(green)(3).color(green)(622464)*10^color(green)(15)#

I hope I helped!