How do you solve #8r(3t-2r)-3r(s+2t)-rt#?

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Answer 1 · 2017-09-19T04:56:04

#-16r^2+17rt-3rs#

You definitely cannot solve for anything, it is an expression, not an equation. I hope you meant to just simplify, if so, here you go!

#8r(3t-2r)-3r(s+2t)-rt#

First, distribute everything to remove the parentheses:

#(24rt-16r^2)+(-3rs-6rt)-rt#

Combine like terms:

#-16r^2 +(24rt-6rt -rt) -3rs#

#-16r^2+17rt-3rs#