Hi there! I need one more help please? Thanks!

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1 Answer
Sep 20, 2017

( y^2 + 2y)/(y+1)

Explanation:

y^2-y-6) = (y -3)(y+2)

y^2+y = y ( y + 1) so

{ y^2(y-3)(y+2)}/{(y-3)y(y+1)}

(y-3)/(y-3) = 1

y^2/y = y/1

Dividing out common terms gives

{y(y+2)/(y+1) multiplying across the parenthesis gives

(y^2 + 2y)/ (y+1)

y cannot be -1 because the denominator would become zero and the term would become undefined or infinite.

( -1+1) = 0