How do you simplify #(4k + 4) \div \frac { 5k + 5} { 8}#?

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Answer 1 · 2017-09-20T15:37:39

#32/5 = 6 2/5#\

Write both factors as fractions and factorise to begin with.

#(4k+4)/1 div (5k+5)/8#

#=(4(k+1))/1 div (5(k+1))/8#

#= (4(k+1))/1 xx 8/(5(k+1))" "larr# multiply by the reciprocal

#= (4cancel((k+1)))/1 xx 8/(5(cancel(k+1)))" "larr# cancel like factors

#=32/5" "larr# multiply straight across

#= 6 2/5#