#-16 = 16x^2# - how many solutions does this equation have?

1 Answer
Gazza
Sep 20, 2017

No real solutions

Explanation:

#-16 = 16x^2#
Let start by subtracting #color(red)(16x^2)# to both side
#-16 - color(red)(16x^2) = 16x^2 - color(red)(16x^2)#
#-16x^2 - 16=0#
Transfer #-16# on the right side
#-16x^2 = 0 + 16#
#-16x^2 = 16#
Divide both sides by #color(green)(-16)#
#(16x^2)/color(green)(-16) = 16/color(green)(-16)#
#x^2 = -1#
Take square root
#x = +- sqrt(-1)#

Hence,
No real solutions

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