First we switch sides from
43=-5(y+11)+7y43=−5(y+11)+7y to -5(y+11)+7y=−5(y+11)+7y=.
We will remove the 7y7y and the 43=43= and focus on the rest.
We will distribute parentheses/brackets using:
a(b+c)=ab+aca(b+c)=ab+ac.
aa would be -5−5, bb would be yy and cc would be 1111 in this case.
Using a(b+c)=ab+aca(b+c)=ab+ac, we know that -5*y-5*11−5⋅y−5⋅11. Multiply -5*y=-5y−5⋅y=−5y and 5*11=555⋅11=55. Therefore the equation would be (with the 7y7y) -5y-55+7y−5y−55+7y.
Next, we group like terms: -5y+7y-55−5y+7y−55, and then add -5y+7y=2y−5y+7y=2y.
The whole equation will then be 2y-55=432y−55=43. Add 5555 to both sides:
2y-55color(blue)+color(blue)55=43color(blue)+color(blue)552y−55+55=43+55 and simplify it to be 2y=982y=98.
Divide both sides by 22 and you get y=49y=49.