How do you evaluate #7^ { 2} ( 3 1/2 \div 7.0) \div ( - 2) + 9 3/ 4#?

1 Answer
EZ as pi
Sep 21, 2017

#(-10)/4 = -2 1/2#

Explanation:

#7^2(color(red)(3 1/2 div 7)) div (-2) + 9 3/4" "larr#Simplify inside the brackets.

#=7^2(color(red)(7/2 xx1/7 )) div (-2) + 9 3/4#
#" "darr#
#=49(color(red)(1/2 )) div (-2/1) + 9 3/4#

#=color(blue)(49/1 xx1/2xx1/-2) + 9 3/4#

#=" "color(blue)(-49/4) " "+" "39/4#

#=" "(-10)/4#

#=-2 1/2#

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