How do you solve # ( x - 5) ( x - 2) = 0#?

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Answer 1 · 2017-09-21T22:56:38

#x=5" or "x=2#

#(x-5)(x-2)=0#

For the above to be true then either:

#(x-5)# must be zero

OR

#(x-2)# must be zero

So, we have:

Either

#x-5=0#

#impliescolor{red}(x=5)#

OR

#x-2=0#

#impliescolor{red}(x=2)#