How do you evaluate #(2x-3)(3x+2)#?

2 Answers
ErmWhat
Sep 22, 2017

#6x^2-5x-6#

Explanation:

You just have to expand it.

#(2x-3)(3x+2)= (2x)(3x)-3(3x)+2(2x)+2(-3)=6x^2-9x+4x-6=6x^2-5x-6#

And that's the answer!

Jim G.
Sep 22, 2017

#6x^2-5x-6#

Explanation:

#"each term in the second bracket is multiplied by each"#
#"term in the first bracket"#

#(color(red)(2x-3))(3x+2)#

#=color(red)(2x)(3x+2)color(red)(-3)(3x+2)#

#=(color(red)(2x)xx3x)+(color(red)(2x)xx2)+(color(red)(-3)xx3x)+(color(red)(-3)xx2)#

#=6x^2+4x-9x-6#

#=6x^2-5x-6#

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