What is the standard form of #f(x)=(2x-3)(x-2)^2+4x-5 #?

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Answer 1 · 2017-09-23T11:57:34

The standard form is # f(x) = 2x^3-11x^2+24x-17 #

# f(x) = (2x-3)(x-2)^2 +4x -5 # or

# f(x) = (2x-3)(x^2-4x+4) +4x -5 # or

# f(x) = 2x^3-8x^2+8x-3x^2+12x-12+4x -5 # or

# f(x) = 2x^3-11x^2+24x-17 #

A standard form of cubic equation is #f(x) = ax^3 + bx^2 + cx + d # .

Here, the standard form is # f(x) = 2x^3-11x^2+24x-17 # Where

#a=2, b=-11,c=24 and d= =17# [Ans]