Question

Question #6d927

Answer 1

See the step-by-step explanation below.

The balanced chemical equation is:

`2` `Al_"(s)" + 3` `Br_(2(l)) -> 2` `AlBr_(3(s))`

Explanation:

We begin with:

`Al_"(s)" + Br_(2(l)) -> AlBr_(3(s))`

On the right-hand side `Br` is in groups of 3 and on the left it is in groups of 2. The neatest way to balance the equation is to take 3 moles of `Br_2`, which is 6 moles of `Br`, and yields 2 moles of `AlBr_3`.

`Al_"(s)" + 3` `Br_(2(l)) -> 2` `AlBr_(3(s))`

Now we note that there are 2 moles of `Al` on the right and only 1 on the left, so we need to multiply the number of moles of `Al` on the left by 2:

`2` `Al_"(s)" + 3` `Br_(2(l)) -> 2` `AlBr_(3(s))`

The quantities of each element are the same on each side, so the equation is balanced.