How do you evaluate #2\frac { 1} { 6} - ( - \frac { 8} { 3} ) + ( - 4\frac { 7} { 4} ) #?

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Answer 1 · 2017-09-24T14:59:04

=#10\frac {7} {12}#

#2\frac { 1} { 6} - ( - \frac { 8} { 3} ) + ( - 4\frac { 7} { 4} )#

Writing as improper fractions,

=#\frac {2*6 +1} { 6} - ( - \frac { 8} { 3} ) + ( -\frac { 4*4 +7} { 4} )#

=#\frac {13} { 6} - ( - \frac { 8} { 3} ) + ( -\frac { 23} { 4} )#

open the brackets,

=#\frac {13} { 6} + \frac { 8} { 3} -\frac { 23} { 4}#

making the denominators equal,

=#frac {13} {6}(2/2)+\ frac {8}{3}(4/4)-\frac{23}{4}(3/3)#

=#frac {26} {12}+\ frac {32}{12}-\frac{69}{12}#

=#frac {26 + 32 + 69} {12}#

=#frac {127} {12}#

Writing in mixed fraction form,

=#10\frac {7} {12}#