Question

How do you evaluate `6m ^ { 3} n ^ { 3} \cdot 8m ^ { 2} n`?

Answer 1

`48m^5n^4`

Explanation:

I would break this in 3 parts:

For the nonvariables,
`6•8=48`

For variable m and n, we are following the rule used for products of powers, which is `a^ba^c=a^(b+c)`

`m^3 • m^2= m^(3+2) = m^5`

`n^3 • n = n^(3+1) = n^4`

When combined:
`48m^5n^4`