How do you divide #(3+10i)^2#?
1 Answer
Sep 25, 2017
Explanation:
There is no division involved in this problem.
However,
# (3+10i)^2 = (3+10i)(3+10i) #
# " " = (3)(3)+(3)(10i) + (3)(10i) + (10i)(10i) #
# " " = 9 + 60i + 100i^2 #
# " " = 9 + 60i - 100 \ \ \ \ \ \ \ \ (because i^2=-1)#
# " " = -91 + 60i #
