How do you evaluate #(1.03 \times 10^9)- ( 4.77 \times 10^7)#?

1 Answer
EZ as pi
Sep 26, 2017

#=9.823 xx 10^8#

Explanation:

Scientific notation is a way of writing very big and very small numbers without having to use all the zeros. As far as possible try not to change back to decimal form to do operations.

In algebra: #8x^2 -5x^2 = 3x^2" "larr# add like terms

In scientific notation, use the same powers of #10#

#1.03 xx10^9 - 4.77xx10^7#

#=10.3 xx 10^8 -0.477xx10^8" "larr# same powers of 10

#= 9.823 xx 10^8" "larr# answer is in scientific notation

If we had used #10^7#

#" "1.03 xx10^9 - 4.77xx10^7#

#= 103 xx 10^7 -4.77xx10^7#

#=98.23 xx 10^7" "larr# change into scientific notation

#=9.823 xx 10^8#

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