Question

How do you solve `3x+3+(-1)+2x=11`?

Answer 1

`x=9/5`

Explanation:

Simplify the left side first.

`3x+3-1+2x =11`

`3x+2x +2 =11`

`5x +2color(blue)(-2)=11color(blue)(-2)" "larr` subtract 2 on both sides

`5x = 9" "larr` divide by `5`

`(5x)/5 =9/5`

`x=9/5`

Answer 2

`x=1 4/5`

Explanation:

Given
`color(white)("XXX")3x+3+(-1)+2x=11`
Working on the left side first,
group the terms including `x` and the constant terms separately
`color(white)("XXX")(3x+2x)+(3-1)=11`
and simplify
`color(white)("XXX")5x+2=11`

Subtract `2` from both sides to isolate the `x` term on the left and a constant term on the right.
`color(white)("XXX")5x=9`

Divide both sides by `5` to isolate a single `x` on the right
#color(white)("XXX")x=9/5= 1 4/5