Question

Question #13154

Answer 1

Final velocity `v=24.54 m/s`
distance Travel`s=65.51m`

Explanation:

Initial velocity of snowmobile `v_o=14 m/s`
Acceleration `a=3.1 m/s^2`
time `t=3.4 sec`
Final Velocity `v=?`
Distance traveled `s=?`

To calculate Final Velocity
Using Newton's First equation of Motion
`v=v_o +at`
`=>v=14+(3.1)(3.4)=14+10.54=24.54 m/s`
Final Velocity `v=24.54 m/s`

To calculate travel distance
Using Newton's Third equation of Motion
`v^2=v_o^2+2as`
`s=(v^2-v_o^2)/(2a)`
`s=((24.54)^2-(14)^2)/(2(3.1))=(602.21-196)/6.2=406.21/6.2=65.51m`
`s=65.51m`