Question #53498

Question

927 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-27T00:33:54

#-35a^5b^5c^5#

If you mean this:
#(-7a^4bc^3)(5ab^4c^2)#

I'll break this into four parts:

Multiply the non-variables in the usual way.
#-7times5 =-35#

The rule for multiplying with powers is #a^b times a^c = a^(b+c)#, and we are using it to multiply #a, b, c# on their own.

#a^4 times a = a^(4+1)= a^5#

#btimesb^4= a^(1+4)=b^5#

#c^2 times c^3=c^(2+3)=c^5#

When combining all of this, it would be #-35a^5b^5c^5#