Question

A `25.00*mL` volume of acetic acid was titrated with `28.33*mL` of `0.953*mol*L^-1` `NaOH(aq)`.... What is the concentration of acetic acid?

What is the concentration of acetic acid?

Answer 1

`"Molarity HOAc"=1.080*mol*L^-1`

Explanation:

We use the quotient....

`"Concentration"="Moles of solute"/"Volume of solution"`

And we also reference the stoichiometrically balanced equation...

`HOAc(aq)+NaOH(aq)rarrNaOAc(aq) + H_2O(l)`

.....and this establishes the 1:1 stoichiometry.....

`"Moles of NaOH"=28.33xx10^-3*Lxx0.953*mol*L^-1=0.0270*mol`.

And this molar quantity of `HOAc` was clearly contained in the `25.00*mL` volume....

`"Concentration"=(0.0270*mol)/(25.00xx10^-3*L)=1.080*mol*L^-1`.

This is on the stronger end of vinegars that you would use in salad dressing or put on your chips.