Question #ea8c2

1 Answer
Sep 27, 2017

Assuming that you mean an imaginary number, this is true.

Explanation:

Essentially, you can't square root a negative number, because if you multiply two negative numbers together you get a positive number. (Try #-5times-5#)
Mathematicians weren't going to let a little thing like impossibility get in their way, so they decided to use imagination.

Basically, we let #sqrt(-1)= i# and then multiply anything by #i# that's imaginary that we want to use. For example, the notation #4i# means 4 times #sqrt(-1)#, or #sqrt(-4)#.

This is very useful when solving quadratic equations for example.

Try solving #x^2-5x+8# -
#(x+5/2)^2 +7/4=0#
#(x+5/2)^2=-7/4#
#x+5/2=sqrt(-7/4)#
now you can't really get the square root of negative #7/4#, so you have to multiply by #i#:
#x+5/2=(sqrt(7)i)/sqrt4#
#x+5/2=(sqrt(7)i)/2#
#x=-5/2+(sqrt(7)i)/2#

graph{x^2-5x+8 [-5, 10, -5, 10]} notice how the graph of this equation doesn't cross the x-axis. This is because it has no real roots as both the roots are imaginary - they have #i# in them.