Question

Question #9605d

Answer 1

`x=(-8+-sqrt(-144))/8`

Explanation:

Right now you have an equation in the form `ax^2+bx+c=0`, where:
`a=4`
`b=8`
`c=13`

The quadratic formula is `x=(-b+-sqrt(b^2-4ac))/(2a)`

By putting our values in we get `x=(-8+-sqrt(8^2-4(4*13)))/(2*4)`

`x=(-8+-sqrt(64-208))/8`

`x=(-8+-sqrt(-144))/8`

Unles a value is meant to be negative then the equation is unsolvable.