Question #9605d

1 Answer
Sep 28, 2017

#x=(-8+-sqrt(-144))/8#

Explanation:

Right now you have an equation in the form #ax^2+bx+c=0#, where:
#a=4#
#b=8#
#c=13#

The quadratic formula is #x=(-b+-sqrt(b^2-4ac))/(2a)#

By putting our values in we get #x=(-8+-sqrt(8^2-4(4*13)))/(2*4)#

#x=(-8+-sqrt(64-208))/8#

#x=(-8+-sqrt(-144))/8#

Unles a value is meant to be negative then the equation is unsolvable.